Difference between revisions of "Chapter 2: An ancient theorem and a modern question"

Line 27: Line 27:
Or more generally:
Or more generally:


<math> 2^a \cdot 2^b = 2^{a+b} <\math>
<math> 2^a \cdot 2^b = 2^a+b <\math>


== Preliminaries ==
== Preliminaries ==
83

edits