Difference between revisions of "Maxwell's Equations"

Revision as of 18:19, 8 March 2020

Joe Schmoe (b. xxxx)

Title xxxx

$$\nabla \times \mathbf{B} = \mu_0 \mathbf{J} + \frac{1}{c^2} \frac{\partial \mathbf{E}}{\partial t}$$

$$\nabla \times \mathbf{E} = - \frac{\partial \mathbf{B}}{\partial t}$$

$$\nabla \cdot \mathbf{B} = 0$$

$$\nabla \cdot \mathbf{E} = \frac{\rho}{\epsilon_0}$$

This formulation assumes no charge $$\rho=0$$ and $$J=0$$. One common example of these conditions is a vacuum.

$$\nabla \times \mathbf{B} = +\frac{1}{c^2} \frac{\partial \mathbf{E}}{\partial t}$$

$$\nabla \times \mathbf{E} = - \frac{\partial \mathbf{B}}{\partial t}$$

$$\nabla \cdot \mathbf{B} = 0$$

$$\nabla \cdot \mathbf{E} = 0$$

@@ Line 4: / Line 4: @@
-This formulation assumes no charge $$\rho=0$$ and $$J=0$$. One common example of these conditions is a vacuum.
 : $$\nabla \times \mathbf{B} = \mu_0 \mathbf{J} + \frac{1}{c^2} \frac{\partial \mathbf{E}}{\partial t}$$
 : $$\nabla \times \mathbf{E} = - \frac{\partial \mathbf{B}}{\partial t}$$
 : $$\nabla \cdot \mathbf{B} = 0$$
 : $$\nabla \cdot \mathbf{E} = \frac{\rho}{\epsilon_0}$$
+This formulation assumes no charge $$\rho=0$$ and $$J=0$$. One common example of these conditions is a vacuum.
+: $$\nabla \times \mathbf{B} = +\frac{1}{c^2} \frac{\partial \mathbf{E}}{\partial t}$$
+: $$\nabla \times \mathbf{E} = - \frac{\partial \mathbf{B}}{\partial t}$$
+: $$\nabla \cdot \mathbf{B} = 0$$
+: $$\nabla \cdot \mathbf{E} = 0$$
 == Resources: ==
 *[https://en.wikipedia.org/wiki/Maxwell%27s_equations Maxwell's Equations]
 == Discussion: ==