Difference between revisions of "Joe Rogan Experience 1628 - Eric Weinstein (Spotify Content)"
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|title=Joe Rogan Experience #1628 - Eric Weinstein | |title=Joe Rogan Experience #1628 - Eric Weinstein | ||
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|host=[ | |host=[https://twitter.com/joerogan Joe Rogan] | ||
|guests=[[Eric Weinstein]] | |guests=[[Eric Weinstein]] | ||
|length=03:17:14 | |length=03:17:14 | ||
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|next=New Physics?? What did Fermilab just discover? A chat with Dan Hooper (YouTube Content) | |next=New Physics?? What did Fermilab just discover? A chat with Dan Hooper (YouTube Content) | ||
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'''Joe Rogan Experience #1628''' was an interview with [[Eric Weinstein]] by [ | '''Joe Rogan Experience #1628''' was an interview with [[Eric Weinstein]] by [https://twitter.com/joerogan Joe Rogan] on the Joe Rogan Experience. Eric showed the latest version of [[Theory of Geometric Unity]]. | ||
{{#widget:SpotifyPodcast|podcast=6Qyuj2pDUQrprzN0qCJP16|height=156|width=35%}} | {{#widget:SpotifyPodcast|podcast=6Qyuj2pDUQrprzN0qCJP16|height=156|width=35%}} | ||
Latest revision as of 00:58, 20 October 2022
This article is a stub. You can help us by editing this page and expanding it.| Joe Rogan Experience #1628 - Eric Weinstein | |
| Information | |
|---|---|
| Host(s) | Joe Rogan |
| Guest(s) | Eric Weinstein |
| Length | 03:17:14 |
| Release Date | 2 April 2021 |
| Links | |
| Spotify | Watch |
| Portal Blog | Read |
| All Appearances | |
Joe Rogan Experience #1628 was an interview with Eric Weinstein by Joe Rogan on the Joe Rogan Experience. Eric showed the latest version of Theory of Geometric Unity.
Description
Eric Weinstein is a mathematician, economist, managing director at Thiel Capital, and host of "The Portal" podcast.
Transcript
This content does not yet have an edited transcript. The Portal Group's Transcript Completion Project generates transcripts for content related to Eric Weinstein and The Portal Podcast. If you would like to contribute, contact Aardvark or Brooke on The Portal Group Discord Server for access to this content's machine-generated transcript.